.25mm是几分管² (14x0.018mm²)

1.给出3个整式,x²,2x+1,x²-2x,从中选取两个整式进行减法运算,然后再因式分解2.计算9.9²+9.9X0.2+0.01=_____;-;=______作业帮
拍照搜题,秒出答案
1.给出3个整式,x²,2x+1,x²-2x,从中选取两个整式进行减法运算,然后再因式分解2.计算9.9²+9.9X0.2+0.01=_____;-;=_____
1.给出3个整式,x²,2x+1,x²-2x,从中选取两个整式进行减法运算,然后再因式分解2.计算9.9²+9.9X0.2+0.01=_____;-;=_____
您好: 1x²-2x-(2x+1)
=x²-1=(x+1)(x-1) 29.9²+9.9X0.2+0.01=9.9²+2x9.9X0.1+0.01=(9.9+0.1)²=100 3;-;=()()=4025 如果本题有什么不明白可以追问,如果满意记得采纳如果有其他问题请采纳本题后另发点击向我求助,答题不易,请谅解,谢谢.祝学习进步!
1.x² - (2x+1)= x² - 2x - 1= (x-1)² - 2= (x-1 + √2) * (x-1 - √2)2.9.9²+9.9X0.2+0.01= (9.9 + 0.1)²= 10²= 100;-;= ()()= 40251/2(8-x)(6-x)=1/2*1/2*8*6 (8-x)(6-x)=24 48-14x+x²=24 x²-14x+24=0 (x-2)(x-12)=0 x=2.x=12?为什么是减14,而不是减2呢?_作业帮
拍照搜题,秒出答案
1/2(8-x)(6-x)=1/2*1/2*8*6 (8-x)(6-x)=24 48-14x+x²=24 x²-14x+24=0 (x-2)(x-12)=0 x=2.x=12?为什么是减14,而不是减2呢?
1/2(8-x)(6-x)=1/2*1/2*8*6 (8-x)(6-x)=24 48-14x+x²=24 x²-14x+24=0 (x-2)(x-12)=0 x=2.x=12?为什么是减14,而不是减2呢?
(8-x)(6-x)=24 x&#178;-6x-8x+48=24x&#178;-14x+48=24-6-8=-14呀1&of 3:&&&&&<small class="preview-attachment-title" data-preview-attachment-id="Attachment_1_Shortcuts_...&&&<small class="preview-attachment-title" data-preview-attachment-id="Attachment_062_Engineer...&&&<small class="preview-attachment-title" data-preview-attachment-id="Attachment_01_Math_Prob...&&potential recommendation reachTo recommend this paper to the <span class="clickable" data-html="data-html" data-placement="top" data-toggle="tooltip" style="border-bottom: 1px dotted black" title="Field is based on suggesti research interests of people d and manual curation.">field, please verify:I have read this paper.This paper is a worthwhile contribution to the literature.recommendLoading PreviewLoading PreviewLoading PreviewMathematics95 PagesSign upBefore we can start your download,please take a moment to join our communityof 22,804,616 academic researchers.&&Connect&&Connect&&Sign up with emailBy signing up, you agree to our&Download PDFs forover 6.1 Million papers Share your paperswith other researchersSee analytics on yourprofile & papersFollow other peoplein your field
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